I am looking at how to wire in the VANS RV-10 door contacts to the EMS220. Is it correct that the GP inputs have to detect a voltage? ie they cannot just see if a contact is open or closed to ground? That being the case, can I run 12v to one side of the switch and the GP wire to the other to sense 12v when it's closed? Or do I need to control a relay with the switches to give 12v or ground output to the GP?
Door Contact Switches
- Thread starter paul330
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One side of the contact should go to ground, the other side of the contact should go to a general purpose input. Then define that GP Input Pin in the EMS Setup as FUNCTION: CONTACT
Sounds simple. However, in the CONTACTS section of the EMS setup guide, it goes on about configuring for 0-2V or 2-5V for OPEN/CLOSED. How can the GP input sense that with no power to the switch. I can't see anything to define the input as simply OPEN/CLOSED.
jakej
Well-Known Member
Paul
do as Dynon says
- it's not about 'power' , just logic. It will work as they say however you're probably confused about the Vans instrucions which are about having leds and warning buzzer requiring power. The magnet operated 'switches' give them the ground to complete the circuit.
Jake J
do as Dynon says
- it's not about 'power' , just logic. It will work as they say however you're probably confused about the Vans instrucions which are about having leds and warning buzzer requiring power. The magnet operated 'switches' give them the ground to complete the circuit.Jake J
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- Mar 23, 2005
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The EMS provides a very small amount of power to the switch (5V through 10K of resistance).
With nothing hooked to the pin, it will read 5V because nothing fights the voltage we put on the pin.
Short the pin to ground, and the short wins, and we read 0V.
The resistance is also high enough that if you want to inject your own voltage instead of just a short to ground, that will work too.
With nothing hooked to the pin, it will read 5V because nothing fights the voltage we put on the pin.
Short the pin to ground, and the short wins, and we read 0V.
The resistance is also high enough that if you want to inject your own voltage instead of just a short to ground, that will work too.